Example: input -> 10
2
3
4
5
7
Algorithm: In order to solve this problem I used dynamic programming to greatly reduce the number of prime checks I had to do. I formatted the code so that the parameter would be a command line input and thus the first portion of the main function is simple exception catching and error handling. Then because you want the primes between 1 and the given number as long as the number is not negative or 1 then 2 will always be on the prime list so I add it to an ArrayList of Integers. Then I used a for loop to go through all the numbers between 3 and the given number inclusive. To check if the current number is prime I used a step wise test:
Steps:
- Check is the number is even
- If it is then it cannot be prime
- Find the square root of the number
- Check all numbers from the prime list already built and the sort
- If it is evenly divisible by an of these numbers it is not prime
- If it passed the above test then it is prime
Full Code:
import java.util.*;
public class PrimeNumGen {
/* this class takes in 2 numbers for a range, it generates and prints
all the prime numbers in the range given */
public static boolean isPrime(int i, ArrayList<Integer> list){
// this function check if a number if prime
if (i % 2 == 0 && i != 2){
// if the num is divisible by two it is not prime
// unless the num is two
return false;
}
// check all numbers between the number and its sqrt
// if the num is divisble by any of these then it is not prime
int sqrt;
if (Math.sqrt(i) % 0 != 0){
sqrt = ((int) Math.sqrt(i)) + 1;
}
else{
sqrt = (int) Math.sqrt(i);
}
int index = 1;
while (index < list.size() && list.get(index) < sqrt){
if (i % list.get(index) == 0){
return false;
}
index++;
}
return true;
}
public static void main(String[] args) {
if (args.length != 1){
// exit if the command inputs are invalid
System.err.println("Invalid Arguments.");
return;
}
int n;
try{
// try to pull the range
n = Integer.parseInt(args[0]);
}
catch (NumberFormatException e){
// if the given arguments are not ints print an error and exit
System.err.println("Arguments must be integers.");
return;
}
// if either number is negative print an error
if (n < 0){
System.err.println("Arguments cannot be negative.");
return;
}
ArrayList<Integer> primes = new ArrayList <Integer>();
primes.add(2);
// for each number in the range check if the number is a prime
for (int i = 3; i <= n; i++){
if (isPrime(i, primes)){
primes.add(i);
}
}
for (int j = 0; j < primes.size(); j++){
System.out.println(primes.get(j));
}
}
}
No comments:
Post a Comment